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leetcode-230

leetcode 230

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/**
* 2019:10:28
* leetcode-cn-230
* icenaive
*/

/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
/*
* 中序遍历为升序,所以中序遍历一次,存入数组,然后返回第k个就可以
*/
class Solution {
public:
int kthSmallest(TreeNode* root, int k) {
if(1 == k) return root->val;
dfs(root);
return que[k - 1];
}
private:
vector<int> que;
TreeNode *ans;
void dfs(TreeNode* root) {
if(root) {
dfs(root->left);
que.push_back(root->val);
dfs(root->right);
}
}
};

/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
/*
* 中序遍历 迭代
*/
class Solution {
public:
int kthSmallest(TreeNode* root, int k) {
stack<TreeNode *> s;
vector<int> ans;
while(!s.empty() || root) {
while(root){
s.push(root);
root = root->left;
}
TreeNode *temp = s.top();s.pop();
ans.push_back(temp->val);
if(temp->right) root = temp->right;
}
return ans[k - 1];
}
};

// 第k个跳出
class Solution {
public:
int kthSmallest(TreeNode* root, int k) {
stack<TreeNode *> s;
vector<int> ans;
int res = -1;
while(!s.empty() || root) {
while(root){
s.push(root);
root = root->left;
}
TreeNode *temp = s.top();s.pop();
k -= 1;
if(0 == k) {res = temp->val; break;} // 判断是否是第k个
//ans.push_back(temp->val);
if(temp->right) root = temp->right;
}
//return ans[k - 1];
return res;
}
};
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# 递归到第k个结束
# python 实现的 c++的不会
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None

class Solution:
def kthSmallest(self, root: TreeNode, k: int) -> int:
res = None
def dfs(root):
nonlocal k, res
if root.left: dfs(root.left)
k -= 1
if 0 == k:
res = root.val
return
if root.right: dfs(root.right)

dfs(root)
return res