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LoeiJe

:D 获取中...

何以解忧?唯有暴富

leetcode-173

leetcode 173

基本思想是栈模拟中序遍历

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/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
/*
* 2019:10:23-173-icenaive
* 使用栈模拟中序遍历,只是将过程分成三个函数
*/
class BSTIterator {
private:
stack<TreeNode *> s;
public:
BSTIterator(TreeNode* root) {
while(root) {
s.push(root);
root = root->left; // 首先入栈的是根个最左子树
}
}

/** @return the next smallest number */
int next() {
auto temp = s.top()
s.pop();
root = temp->right;
while(root) {
s.push(root);
root = root->left; // 最左节点的右儿子的最左子树
}
return temp->val;
}

/** @return whether we have a next smallest number */
bool hasNext() {
return !s.empty(); // 判断栈是否为空就可以
}
};

/**
* Your BSTIterator object will be instantiated and called as such:
* BSTIterator* obj = new BSTIterator(root);
* int param_1 = obj->next();
* bool param_2 = obj->hasNext();
*/