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合并两个有序链表

合并两个有序链表!

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// 合并两个有序链表.cpp: 定义控制台应用程序的入口点。
//

#include "stdafx.h"
#include <iostream>
using namespace std;

struct ListNode {
int val;
ListNode *next;
ListNode(int x = 0) : val(x), next(NULL) {}
};

class Solution {
public:
ListNode * mergeTwoLists(ListNode* l1, ListNode* l2) {
ListNode *l = new ListNode(0);
ListNode *tem = new ListNode(0);
tem = l;
while (l1 && l2)
{
if (l1->val < l2->val)
{
l->next = new ListNode(0);
l = l->next;
l->val = l1->val;

l1 = l1->next;
}
else
{
l->next = new ListNode(0);
l = l->next;
l->val = l2->val;

l2 = l2->next;
}
}
while (l1)
{
l->next = new ListNode(0);
l = l->next;
l->val = l1->val;

l1 = l1->next;
}
while (l2)
{
l->next = new ListNode(0);
l = l->next;
l->val = l2->val;

l2 = l2->next;
}
l = tem;
l = l->next;
return l;
}
};
int main()
{
ListNode *l1 = new ListNode();
ListNode *tem1 = l1;
ListNode *l2 = new ListNode();
ListNode *tem2 = l2;
for (int i = 1; i < 4; i++)
{
l1->next = new ListNode();
l1 = l1->next;
l1->val = i;

l2->next = new ListNode();
l2 = l2->next;
l2->val = i;
}
l1 = tem1->next;
l2 = tem2->next;
Solution s;
ListNode *l = new ListNode();
l = s.mergeTwoLists(l1, l2);
while (l)
{
cout << l->val << " ";
l = l->next;
}
return 0;
}